document.write( "Question 848569: tom invested some money at 5% and $300 more at 7%. His total annual interest income was $81. How much did tom invest at 5%? \n" ); document.write( "
Algebra.Com's Answer #511181 by swincher4391(1107)\"\" \"About 
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.05x + .07*300 = 81\r
\n" ); document.write( "\n" ); document.write( ".05x + 21 = 81\r
\n" ); document.write( "\n" ); document.write( ".05x = 60\r
\n" ); document.write( "\n" ); document.write( "x = 1200\r
\n" ); document.write( "\n" ); document.write( "Unless the interpretation is that he invested $300 more than what he invested at 5%. I just feel like it should have said \"more than the 5%\"\r
\n" ); document.write( "\n" ); document.write( "Solving it this way:\r
\n" ); document.write( "\n" ); document.write( ".05x + .07(x+300) = 81\r
\n" ); document.write( "\n" ); document.write( "x = 500\r
\n" ); document.write( "\n" ); document.write( "Depends on what the interpretation is. I believe my original interpretation is what he meant. That is to say he took $1200 and put it into the 5% and then he took $300 more and put it into the 7%. The combination of the funds gives him the interest of $81.
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