document.write( "Question 848560: I am helping my daughter do her homework and we are stuck on this question, we are missing a step.\r
\n" ); document.write( "\n" ); document.write( "The area of a table is 44 sq ft, and twice the length is 5 feet shorter than 2 times the width. Find the perimeter of the top.\r
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Algebra.Com's Answer #511173 by Alan3354(69443)\"\" \"About 
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The area of a table is 44 sq ft, and twice the length is 5 feet shorter than 2 times the width. Find the perimeter of the top.
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\n" ); document.write( "L*W = 44 (the area)
\n" ); document.write( "2L + 5 = 2W (length and width deal)
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\n" ); document.write( "L = 44/W
\n" ); document.write( "2L + 5 = 2W
\n" ); document.write( "sub for L
\n" ); document.write( "88/W + 5 = 2W
\n" ); document.write( "88 + 5W = 2W^2
\n" ); document.write( "2W^2 - 5W - 88 = 0
\n" ); document.write( "(W - 8)*(2W + 11) = 0
\n" ); document.write( "W = 8 ft
\n" ); document.write( "L = 5.5 ft
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\n" ); document.write( "P = 2W + 2L = 27 feet
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