document.write( "Question 848438: Two skiers set out together on a long track, one skied a quarter of a mile per hour faster than the other and finished an hour earlier, if both skied 34 miles at what rate did each of them ski \n" ); document.write( "
Algebra.Com's Answer #511144 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! Two skiers set out together on a long track, one skied a quarter of a mile per hour faster than the other and finished an hour earlier, \n" ); document.write( "if both skied 34 miles at what rate did each of them ski \n" ); document.write( ": \n" ); document.write( "let s = speed of the 1st skier \n" ); document.write( "then \n" ); document.write( "(s+.25) = speed of the faster skier \n" ); document.write( ": \n" ); document.write( "Write a time equation; time = dist/speed \n" ); document.write( "1stskier time - fast skier time = 1 hr \n" ); document.write( " \n" ); document.write( "multiply by s(s+.25), to cancel the denominators, resulting in: \n" ); document.write( "34s(s+.25) - 34s = s(s+.25) \n" ); document.write( "34s + 8.5 - 34s = s^2 + .25s \n" ); document.write( "A quadratic equation \n" ); document.write( "s^2 + .25s - 8.5 = 0 \n" ); document.write( "use the quadratic formula to find s, I got a postive solution of \n" ); document.write( "s = 2.793 mph, speed of the 1st skier \n" ); document.write( "then \n" ); document.write( "2.793 + .25 = 3.043 mph, speed of the faster skier \n" ); document.write( "; \n" ); document.write( "; \n" ); document.write( "Confirm this by finding the actual time of each. \n" ); document.write( "34/2.793 = 12.173 hrs \n" ); document.write( "34/3.043 = 11.173 \n" ); document.write( "----------------- \n" ); document.write( "time dif: 1 hr \n" ); document.write( " |