document.write( "Question 848438: Two skiers set out together on a long track, one skied a quarter of a mile per hour faster than the other and finished an hour earlier, if both skied 34 miles at what rate did each of them ski \n" ); document.write( "
Algebra.Com's Answer #511144 by ankor@dixie-net.com(22740)\"\" \"About 
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Two skiers set out together on a long track, one skied a quarter of a mile per hour faster than the other and finished an hour earlier,
\n" ); document.write( "if both skied 34 miles at what rate did each of them ski
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\n" ); document.write( "let s = speed of the 1st skier
\n" ); document.write( "then
\n" ); document.write( "(s+.25) = speed of the faster skier
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\n" ); document.write( "Write a time equation; time = dist/speed
\n" ); document.write( "1stskier time - fast skier time = 1 hr
\n" ); document.write( "\"34%2Fs\" - \"34%2F%28%28s%2B.25%29%29\" = 1
\n" ); document.write( "multiply by s(s+.25), to cancel the denominators, resulting in:
\n" ); document.write( "34s(s+.25) - 34s = s(s+.25)
\n" ); document.write( "34s + 8.5 - 34s = s^2 + .25s
\n" ); document.write( "A quadratic equation
\n" ); document.write( "s^2 + .25s - 8.5 = 0
\n" ); document.write( "use the quadratic formula to find s, I got a postive solution of
\n" ); document.write( "s = 2.793 mph, speed of the 1st skier
\n" ); document.write( "then
\n" ); document.write( "2.793 + .25 = 3.043 mph, speed of the faster skier
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\n" ); document.write( "Confirm this by finding the actual time of each.
\n" ); document.write( "34/2.793 = 12.173 hrs
\n" ); document.write( "34/3.043 = 11.173
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\n" ); document.write( "time dif: 1 hr
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