document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=71451>Question 71451</A>This question is from textbook <A HREF=http://www.amazon.com/exec/obidos/ASIN/0130631833/algebrahomeworkh>Algebra 1 California Edition</A><BR>\n" );
document.write( ": <I><SPAN STYLE=\"word-break: break-all;\"> Chapter 7-8 Parallel and Perpendicular Lines<BR>\n" );
document.write( "Introducing the Concept: Slope and Line Relationships\r<BR>\n" );
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document.write( "Here's my question:<BR>\n" );
document.write( "\"Write an equation for the line containing the given point and perpendicular to the given line.\"<BR>\n" );
document.write( "27. (0,6); y-3x=4<BR>\n" );
document.write( "28. (-2,4); y=2x-3<BR>\n" );
document.write( "29. (0,2); 3y-x=0\r<BR>\n" );
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document.write( "My son just started homeschooling and I am at a complete loss as to how to provide him with help on this part of the chapter.\r<BR>\n" );
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document.write( "Just an FYI:  Chapter 7 \"Graphs and Linear Equations\"  7-8 Exercises Part B #27, #28, #29\r<BR>\n" );
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document.write( "Thank you for any help you can provide us!!!! </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #51110 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley75><B>checkley75(3666)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley75><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=51110\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Y-3X=4<BR>\n" );
document.write( "Y=3X+4 HAS A SLOPE OF 3 SO THE PERPENDICULAR LINE HAS A SLOE OF THE NEGATIVE RECIPROCAL OF 3 WHICH IS -1/3. NOW USIE THE X,Y VALUES TO SOLVE Y=mX+b FOR THE Y INTERCEPT (b).<BR>\n" );
document.write( "6=-1/3*0+b<BR>\n" );
document.write( "6=b SO THE LINE WITH A SLOPE OF -1/3 PASSING THROUGH (0,6) IS<BR>\n" );
document.write( "Y=-1/3X+6<BR>\n" );
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document.write( "Y=2X-3 HAS A SLOPE OF 2 THUS THE PERPENDICULAR SLOPE IS -1/2<BR>\n" );
document.write( "4=-1/2*-2+b<BR>\n" );
document.write( "4+1=b<BR>\n" );
document.write( "5=b SO THE LINE WITH A SLOPE OF -1/2 PASSING THROUGH (-2,4) IS<BR>\n" );
document.write( "Y=-1/2X+5<BR>\n" );
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document.write( "3Y-X=0<BR>\n" );
document.write( "3Y=X<BR>\n" );
document.write( "Y=X/3 HAS A SLOPE OF 1/3 THUS THE PERPENDICULAR SLOPE IS -3<BR>\n" );
document.write( "2=-3*0+b<BR>\n" );
document.write( "2=b SO THE LINE WITH A SLOPE OF -3 PASSING THROUGH (0,2) IS<BR>\n" );
document.write( "Y=-3X+2 </SPAN>\n" );
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