document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=71435>Question 71435</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Solve the following word problem. Be sure to show the equation you use for the solution.<BR>\n" );
document.write( "Science and medicine. A bicyclist rode into the country for 5 h. In returning, her speed was 5 mi/h faster and the trip took 4 h. What was her speed each way?<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #51104 by </B><A HREF=/tutors/aboutme.mpl?userid=Earlsdon><B>Earlsdon(6294)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Earlsdon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=51104\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Using the formula: d = rt where: d = distance, r = rate (speed) and t = time taken for the trip:<BR>\n" );
document.write( "For the outbound trip:<BR>\n" );
document.write( "d = r(5hrs)<BR>\n" );
document.write( "For the return trip:<BR>\n" );
document.write( "d = (r+5)(4hrs) The return rate was 5 mph faster than the outbound trip.<BR>\n" );
document.write( "Now since the distane d is the same in both cases, you can set the first equation equal to the second equation and solve for the rate (speed) r.<BR>\n" );
document.write( "5r = 4(r+5) Simplify.<BR>\n" );
document.write( "5r = 4r+20 Subtract 4r from both sides.<BR>\n" );
document.write( "r = 20 mph for the outbound trip.<BR>\n" );
document.write( "r = 20+5 = 25 mph for the return trip.  </SPAN>\n" );
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