document.write( "Question 848337: 2logX=-1 Solve \n" ); document.write( "

Algebra.Com's Answer #511032 by swincher4391(1107) $\"\"$ $\"About$

You can put this solution on YOUR website!
log(x) = -1/2\r
\n" ); document.write( "\n" ); document.write( "10^log(x) = 10^(-1/2) \r
\n" ); document.write( "\n" ); document.write( " $\"x+=+1%2Fsqrt%2810%29+=++.31623\"$ \n" ); document.write( "

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