document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=848306>Question 848306</A>: <I><SPAN STYLE=\"word-break: break-all;\"> the lengths of the sides of a rectangle are whole numbers. if the rectangles perimeter is 24 units, which of the following could not be the area of the rectangle?<BR>\n" );
document.write( " a. 27 square units<BR>\n" );
document.write( "b. 24 square units<BR>\n" );
document.write( "c. 20 square units<BR>\n" );
document.write( "d. 11 square units </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #511031 by </B><A HREF=/tutors/aboutme.mpl?userid=hamsanash1981@gmail.com><B>hamsanash1981@gmail.com(151)</B></A><img src=\"/images/stars/stars-09.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=hamsanash1981@gmail.com><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=511031\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Given Perimeter = 24 units<BR>\n" );
document.write( "2(l+b)=24<BR>\n" );
document.write( "L+B =12<BR>\n" );
document.write( "Option A can be area of the rectangle as 9*3 is 27 and 9+3 = 12.<BR>\n" );
document.write( "Option B cannot be area of the rectangle as possible  combination area (8*3,12*2,6*4) and their sum is (11,14,10). <BR>\n" );
document.write( "option C can be area as 10*2 is 20 and 10+2 = 12<BR>\n" );
document.write( "option D can be area as 11*1 is 11 and 11+1 = 12 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );