document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=848325>Question 848325</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Please help, I am having problems solving this problem: Plane A leaves an airport in Toronto at 10am. Plane B leaves at 11am from the same airport on the same course and overtakes Plane A in 2.5 hours, if the average speed of Plane B is 300km/hr faster than Plane A, find the speed of each.\r<BR>\n" );
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document.write( "Thanks </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #511028 by </B><A HREF=/tutors/aboutme.mpl?userid=hamsanash1981@gmail.com><B>hamsanash1981@gmail.com(151)</B></A><img src=\"/images/stars/stars-09.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=hamsanash1981@gmail.com><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=511028\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> time taken by plane A for certain distance is 3.5 and Plane B takes 2.5 to cover the same distance.<BR>\n" );
document.write( "Let the speed of Plane A be x then plane B is x+300<BR>\n" );
document.write( "Distance = speed* time<BR>\n" );
document.write( "x*3.5 = 2.5(x+300)<BR>\n" );
document.write( "3.5x = 2.5x + 750<BR>\n" );
document.write( "x = 750<BR>\n" );
document.write( "Speed of Plane A is 750 km/hr and speed of Plane B is 750+300 = 1050 km/hr </SPAN>\n" );
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