document.write( "Question 848321: The base of a triangle is 2cm more than the height. The base is increased by 4cm while the height is the same. The new area is 56cm. Whats the original area?
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Algebra.Com's Answer #511021 by swincher4391(1107)\"\" \"About 
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b = h + 2
\n" ); document.write( "b-2 = h\r
\n" ); document.write( "\n" ); document.write( "After change, our base is b+4\r
\n" ); document.write( "\n" ); document.write( "A = (1/2) * b * h\r
\n" ); document.write( "\n" ); document.write( "56 = (1/2)*(b+4)*(b-2)\r
\n" ); document.write( "\n" ); document.write( "56 = (1/2)(b^2+2b-8)\r
\n" ); document.write( "\n" ); document.write( "112 = b^2 +2b - 8\r
\n" ); document.write( "\n" ); document.write( "b^2 +2b -120 = 0\r
\n" ); document.write( "\n" ); document.write( "(b-10)(b+12) = 0\r
\n" ); document.write( "\n" ); document.write( "b = 10 [ignore b= -12]\r
\n" ); document.write( "\n" ); document.write( "This means h = 8\r
\n" ); document.write( "\n" ); document.write( "original area = 1/2 *(10)*(8) = \"highlight%2840%29\" cm^2
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