document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=71443>Question 71443</A>: <I><SPAN STYLE=\"word-break: break-all;\"> 4x + y = 16,  2x + 3y = 24<BR>\n" );
document.write( "I have tried mul. the 1st equation by -3. Then adding the 2 together.  I have tried mul. 2nd equation by -2, then adding the 2 together.  I have tried y = 16 - 4x, then tried to substitute y into the 2nd equation. I can't seem to figure it out. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #51101 by </B><A HREF=/tutors/aboutme.mpl?userid=Earlsdon><B>Earlsdon(6294)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Earlsdon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=51101\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Solve the system of of equations:<BR>\n" );
document.write( "1) 4x+y = 16<BR>\n" );
document.write( "2) 2x+3y = 24<BR>\n" );
document.write( "Your first step was one in the right direction. Multiply equation 1) by -3 then add the resulting equation to equation 2).<BR>\n" );
document.write( "1a) -12x-3y = -48<BR>\n" );
document.write( "2)....2x+3y = 24<BR>\n" );
document.write( "------------------<BR>\n" );
document.write( "-10x = -24 Divide both sides by -10.<BR>\n" );
document.write( "x = 2.4 Now substitute this value of x into either one of the two original equations and solve for y.<BR>\n" );
document.write( "4x+y = 16 Substitute x = 2.4<BR>\n" );
document.write( "4(2.4) + y = 16 <BR>\n" );
document.write( "9.6 + y = 16 Subtract 9.6 from both sides.<BR>\n" );
document.write( "y = 6.4<BR>\n" );
document.write( "The solution is (2.4, 6.4) </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );