document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=848251>Question 848251</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Use the given conditions to write an equation for the line in point-slope form and general form. Passing through (-9,3) and parallel to the line whose equation is 2x-5y-8=0\r<BR>\n" );
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document.write( "The equation of the line in point-slope form is  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #510974 by </B><A HREF=/tutors/aboutme.mpl?userid=josgarithmetic><B>josgarithmetic(39617)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=josgarithmetic><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=510974\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> NOTE: Edited because of mistake with slope-----Now been corrected.\r<BR>\n" );
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document.write( "The slopes are the same for parallel lines in the plane.  Keeping in the given standard form, The equation you want to find is 2x-5y+c=0.  Solve for c and then substitute the given point needed to be on the line.\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=c=-2x%2B5y ALIGN=MIDDLE  ALT=\"c=-2x%2B5y\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=c=-2%28-9%29%2B5%2A3 ALIGN=MIDDLE  ALT=\"c=-2%28-9%29%2B5%2A3\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=c=18%2B15 ALIGN=MIDDLE  ALT=\"c=18%2B15\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=c=33 ALIGN=MIDDLE  ALT=\"c=33\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "The line then in standard form is <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=highlight%28-2x%2B5y%2B33=0%29 ALIGN=MIDDLE  ALT=\"highlight%28-2x%2B5y%2B33=0%29\"   DISABLED_style= \"max-width:90%; height:auto;\" >.\r<BR>\n" );
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document.write( "You wanted the equation in both point-slope form and in general form.\r<BR>\n" );
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document.write( "GENERAL FORM:<BR>\n" );
document.write( "Solve for y and adjust into general form, variable term plus (or minus) constant term.  Solving for y will give a formula; not a value.\r<BR>\n" );
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document.write( "POINT-SLOPE FORM:<BR>\n" );
document.write( "You will be able to read the slope directly from the \"general\" form or from the standard form; and then use the formula for slope (which is vertical change divided by horizontal change) to obtain the point-slope form.<BR>\n" );
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document.write( "You will see that slope <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=m=2%2F5 ALIGN=MIDDLE  ALT=\"m=2%2F5\"   DISABLED_style= \"max-width:90%; height:auto;\" >.  Doing the steps, you will find <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=highlight%28y-3=%282%2F5%29%28x%2B9%29%29 ALIGN=MIDDLE  ALT=\"highlight%28y-3=%282%2F5%29%28x%2B9%29%29\"   DISABLED_style= \"max-width:90%; height:auto;\" >. </SPAN>\n" );
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