document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=848245>Question 848245</A>: <I><SPAN STYLE=\"word-break: break-all;\"> clay is going to invest 9000$, part at 3% and the rest at 3.5%. what is the most he can invest at 3% and still be guaranteed 300$ interest each year </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #510966 by </B><A HREF=/tutors/aboutme.mpl?userid=swincher4391><B>swincher4391(1107)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=swincher4391><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=swincher4391><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=510966\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let x be the amount invested at 3% and (9000-x) be the part invested 3.5%.\r<BR>\n" );
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document.write( ".03x + .035(9000-x) >= 300\r<BR>\n" );
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document.write( ".3x + 315 - .035x >= 300\r<BR>\n" );
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document.write( "-.005x >= -15\r<BR>\n" );
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document.write( "x <= 3000\r<BR>\n" );
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document.write( "Which means he can put at most $3000 in the 3% to guarantee the return of $300. </SPAN>\n" );
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