document.write( "Question 848229: A bus traveled 560 km at a constant rate. A truck traveled the same distance 10km/hr faster than the bus in 1 hour less time. Find the constant rate of the bus. How long did it take the truck to travel the 560km? \n" ); document.write( "

Algebra.Com's Answer #510953 by swincher4391(1107) $\"\"$ $\"About$

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Let x be the speed at which the bus is travelling. Let y be the time in which it took for the truck to travel the 560km.\r
\n" ); document.write( "\n" ); document.write( "distance = rate * time\r
\n" ); document.write( "\n" ); document.write( "(bus) 560 = x km/h * y+1 hours\r
\n" ); document.write( "\n" ); document.write( "(truck) 560 = (x+10) * y\r
\n" ); document.write( "\n" ); document.write( "560 = xy + x
\n" ); document.write( "560 = xy + 10y\r
\n" ); document.write( "\n" ); document.write( "xy+x = xy+10y\r
\n" ); document.write( "\n" ); document.write( "x = 10y\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "560 = 10y^2 + 10y\r
\n" ); document.write( "\n" ); document.write( "56 = y^2 + y\r
\n" ); document.write( "\n" ); document.write( "y^2 +y - 56 = 0\r
\n" ); document.write( "\n" ); document.write( "(y-7)(y+8) = 0\r
\n" ); document.write( "\n" ); document.write( "y = 7 (can't have y=-8)\r
\n" ); document.write( "\n" ); document.write( "x = 70\r
\n" ); document.write( "\n" ); document.write( "So the bus traveled 70 km/h.\r
\n" ); document.write( "\n" ); document.write( "And it took the truck 7 hours to travel the 560km. \n" ); document.write( "

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