document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=848224>Question 848224</A>: <I><SPAN STYLE=\"word-break: break-all;\"> How do I identify the slope and y-intercept of the graph of each equation and graph that equation? problem: y=-3x +3 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #510951 by </B><A HREF=/tutors/aboutme.mpl?userid=swincher4391><B>swincher4391(1107)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=swincher4391><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=swincher4391><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=510951\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Slope-intercept form :  y = mx+b  <-- remember this.\r<BR>\n" );
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document.write( "m is our slope.  b is our intecept.\r<BR>\n" );
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document.write( "You may think of m as move and b as begin, though this is not what they really stand for.\r<BR>\n" );
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document.write( "so m = -3 <--- slope (perhaps think of this as -3 / 1]\r<BR>\n" );
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document.write( "b = 3 <--- y-intercept.\r<BR>\n" );
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document.write( "So I begin at y=3,\r<BR>\n" );
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document.write( "Then I move down 3 and right 1 and plot a point. You could connect the dots at this point, but I always do 3 points so instead make a point that goes up 3 and left 1 as well. It should be a downward sloping line that goes through (-1,6), (0,3), (1,0) </SPAN>\n" );
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