document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=848200>Question 848200</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A 12% salt solution is to be mixed with a 7% salt solution to obtain 15 liters of a 10% salt solution.  How much of each solution should be used? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #510940 by </B><A HREF=/tutors/aboutme.mpl?userid=swincher4391><B>swincher4391(1107)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=swincher4391><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=swincher4391><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=510940\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let x be our 12%, let 15-x be our 7%\r<BR>\n" );
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document.write( ".12 * x + .07(15-x) = .10*15\r<BR>\n" );
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document.write( ".12x + 1.05 - .07x = 1.5\r<BR>\n" );
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document.write( "solving for x we get  x= 9L < ---- 12% salt solution\r<BR>\n" );
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document.write( "That means 6L for our 7%\r<BR>\n" );
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document.write( " </SPAN>\n" );
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