document.write( "Question 848163: How do you find the dimensions of a rectangle if it's perimeter is 170 feet and its area is 2800 square feet. \n" ); document.write( "
Algebra.Com's Answer #510917 by swincher4391(1107)\"\" \"About 
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170 = 2L + 2W\r
\n" ); document.write( "\n" ); document.write( "2800 = L*W\r
\n" ); document.write( "\n" ); document.write( "2800/W = L\r
\n" ); document.write( "\n" ); document.write( "170 = 2*(2800/W) + 2W \r
\n" ); document.write( "\n" ); document.write( "170 = 5600/W + 2W\r
\n" ); document.write( "\n" ); document.write( "170W/W = 5600/W + 2W^2/W\r
\n" ); document.write( "\n" ); document.write( "W isn't 0, so we can ignore the denominator.\r
\n" ); document.write( "\n" ); document.write( "170W = 5600 + 2W^2\r
\n" ); document.write( "\n" ); document.write( "2W^2 - 170W +5600\r
\n" ); document.write( "\n" ); document.write( "2(W^2 - 85W + 2800)\r
\n" ); document.write( "\n" ); document.write( "This has no real solution. You can compute this by taking b^2 - 4ac, which is clearly less than 0.\r
\n" ); document.write( "\n" ); document.write( "Another thing we can notice that confirms this is say our rectangle has the same length and width. This maximizes our area (also known as a square). Then each side would have 42.5, and so 42.5^2 = 1806.25 which is the maximum area possible. This is not necessary to know, but it confirms that there is no real solution.\r
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