document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=848076>Question 848076</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The area of a triangle is 95 square feet.If the height is 5 more than the base, find the length of the height and base of the triangle.  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #510861 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=510861\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The area of a triangle is 95 square feet.If the height is 5 more than the base, find the length of the height and base of the triangle. <BR>\n" );
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document.write( "Let base = x<BR>\n" );
document.write( "Then height = x+5<BR>\n" );
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document.write( "Equation:<BR>\n" );
document.write( "x(x+5) = 95<BR>\n" );
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document.write( "x^2 + 5x - 95 = 0<BR>\n" );
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document.write( "x = [-5 +- sqrt(25-4*-95)]/2<BR>\n" );
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document.write( "x = [-5 +- sqrt(405)]/2<BR>\n" );
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document.write( "x = [-5 +- 9sqrt(5)]/2<BR>\n" );
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document.write( "Positive solution:<BR>\n" );
document.write( "x = (-5+9sqrt(5))/2 = 7.56 <BR>\n" );
document.write( "x+5 = 12.58<BR>\n" );
document.write( "=====================<BR>\n" );
document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
document.write( "===================== </SPAN>\n" );
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