document.write( "Question 847965: The diagonal and the longer side of a rectangular plot are together three times the length of the shorter side. If the longer side exceeds the shorter side by 150 ft, what is the area of the plot?\r
\n" ); document.write( "\n" ); document.write( "I was able to come up with the following:\r
\n" ); document.write( "\n" ); document.write( "let s = shorter side
\n" ); document.write( "longer side = s + 150
\n" ); document.write( "then 3s = diagonal + (s + 150)\r
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Algebra.Com's Answer #510851 by ewatrrr(24785)\"\" \"About 
You can put this solution on YOUR website!
 
\n" ); document.write( "Hi,
\n" ); document.write( "let s = shorter side
\n" ); document.write( "longer side = (s + 150)
\n" ); document.write( " 3s = diagonal + (s + 150) Yes, good work
\n" ); document.write( " 2s - 150 = \"sqrt%28s%5E2+%2B+%28s%2B150%29%5E2%29\" |Squaring both Sides
\n" ); document.write( "4s^2 - 600s + 150^2 = 2s^2 + 300s + 150^2
\n" ); document.write( " 2s^2 = 900s
\n" ); document.write( " s = 450ft, shorter side. The longer side is 600ft
\n" ); document.write( "Area is \"%28450ft%29%28600ft%29\" \n" ); document.write( "
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