document.write( "Question 848064: a) How large is the area that lies under the standard normal curve bound between –2.03 and -1.23? \r
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\n" ); document.write( "\n" ); document.write( "b) How large is the area that lies under the standard normal curve to the right of 1.63?
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Algebra.Com's Answer #510846 by swincher4391(1107)\"\" \"About 
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a) P[-2.03\n" ); document.write( "\n" ); document.write( "Think about what this means. We want all the area left of 1.23, but we want to take away the area left of -2.03.\r
\n" ); document.write( "\n" ); document.write( "P[Z<1.23] - P[Z < -2.03]\r
\n" ); document.write( "\n" ); document.write( "Notice that the area left of -2.03 is the area right of 2.03, or since the entire area is 1, it's 1 -P[Z<2.03]\r
\n" ); document.write( "\n" ); document.write( "So we have:\r
\n" ); document.write( "\n" ); document.write( "P[Z<1.23] - (1-P[Z<2.03])\r
\n" ); document.write( "\n" ); document.write( "Now we can use the standard normal table. Let's call the standard normal lookup function \"phi\". \r
\n" ); document.write( "\n" ); document.write( "\"phi%281.23%29+-+%281-phi%282.03%29%29\"\r
\n" ); document.write( "\n" ); document.write( "\".8907+-+%281-.9788%29+=+highlight%280.8695%29\"\r
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\n" ); document.write( "\n" ); document.write( "2. P[Z>1.63]. As I mentioned before, since the entire area under the curve is 1, then 1- P[Z<1.63] is another way to represent this.\r
\n" ); document.write( "\n" ); document.write( "Using \"phi\"\r
\n" ); document.write( "\n" ); document.write( "\"1+-+phi%281.63%29\" \r
\n" ); document.write( "\n" ); document.write( "\"1-.9484+=+highlight%28.0516%29\"\r
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