document.write( "Question 848023: P(-3,1), Q(2,5) and R(7,a) are three points in the cartesian plane. Find the values of ''a'' in each case if
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document.write( "P,Q and R are collinear
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document.write( "PQR=90 degrees
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document.write( "PR=QR \n" );
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Algebra.Com's Answer #510837 by josgarithmetic(39617)![]() ![]() ![]() You can put this solution on YOUR website! \r \n" ); document.write( "\n" ); document.write( "First find equation of line PQ. \n" ); document.write( "Slope \n" ); document.write( "y=mx+b \n" ); document.write( "b=y-mx \n" ); document.write( "Use the point P or Q, find b value. \n" ); document.write( " \n" ); document.write( "Equation for PQ is \n" ); document.write( "- \n" ); document.write( "R is collinear: Use x=7 to find \"a\".-------- \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "Point R(7, 42/5) Collinear with P and Q.\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "PQR to be 90 degree--- \n" ); document.write( "That is perpendicular to eachother, PQ and QR. \n" ); document.write( "The line QR would have slope \n" ); document.write( "The line for QR in this way, which will contain Q, will be y=-(5/4)x+b; here, this b is going to be different from the one for PQ. \n" ); document.write( "b=y+(5/4)x \n" ); document.write( "and using point Q(2, 5), \n" ); document.write( " \n" ); document.write( "Line QR is \n" ); document.write( "- \n" ); document.write( "What then is R? What is y when x=7? \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "Point R is (7, -5/4).\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "PR=QR------- \n" ); document.write( "Use the distance formula for PR and QR. The variable will be a. \n" ); document.write( "- \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Equating PR=QR and squaring both sides gives \n" ); document.write( " \n" ); document.write( "-... \n" ); document.write( "You continue this to find a? \n" ); document.write( " |