document.write( "Question 847979: how many ounces of pure silver that cost $8.50 an ounce must be mixed with 100 oz of a silver alloy that cost $5.00 an ounce to make an alloy that cost $6.50 an ounce. \n" ); document.write( "
Algebra.Com's Answer #510828 by josgarithmetic(39618)\"\" \"About 
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Let z = the ounces of silver to add.\r
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\n" ); document.write( "\n" ); document.write( "\"%288.50z%2B5%2A100%29%2F%28z%2B100%29=6.50\"\r
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\n" ); document.write( "\n" ); document.write( "See the lesson, http://www.algebra.com/tutors/Two-Part-Mixture-with-one-material-quantity-unknown.lesson?content_action=show_dev
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