document.write( "Question 847916: please help me solve this equation
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document.write( "log base6(12) + log base 6(3) = (2/3)x
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document.write( "log base6(36)= (2/3)x \n" );
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Algebra.Com's Answer #510756 by rothauserc(4718)![]() ![]() You can put this solution on YOUR website! log base6(12) + log base 6(3) = (2/3)x \n" ); document.write( "use property of multiplying like base logs \n" ); document.write( "log base6(36)= (2/3)x \n" ); document.write( "note that log base6 (36) = 2 \n" ); document.write( "2 = (2/3) x \n" ); document.write( "x = 3 \n" ); document.write( " \n" ); document.write( " |