document.write( "Question 847878: Find three consecutive positive integers such that that product of the first and third, minus the second, is 1 more than 6 times the third.
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Algebra.Com's Answer #510728 by hamsanash1981@gmail.com(151) $\"\"$ $\"About$

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Let the consecutive positive integers be x, x+1, x+2
\n" ); document.write( "then, x*(x+2) - (x-1)-1=6(x+2)
\n" ); document.write( " $\"x%5E2%2B2x-x-1-1=6x%2B12\"$
\n" ); document.write( " $\"x%5E2-5x+-14+=+0\"$
\n" ); document.write( " $\"%28x-7%29%28x%2B2%29=0\"$
\n" ); document.write( " $\"x+=+7%2C+x=+-2\"$
\n" ); document.write( "x = -2 is eliminated as it is given that integers are positive
\n" ); document.write( "When x = 7 the numbers are 7,8,9 and smallest number 7. \n" ); document.write( "

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