document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=847869>Question 847869</A>: <I><SPAN STYLE=\"word-break: break-all;\"> a father is 42 years old,his son is 10 years old and his daughter is 16 years old.\r<BR>\n" );
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document.write( "a) In how many years will the age of the father be the triple of that of his son?<BR>\n" );
document.write( "b) In how many years will the age of the father be the sum of those of his children?<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #510719 by </B><A HREF=/tutors/aboutme.mpl?userid=hamsanash1981@gmail.com><B>hamsanash1981@gmail.com(151)</B></A><img src=\"/images/stars/stars-09.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=hamsanash1981@gmail.com><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=510719\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> a) let be the no of years taken to triple the age of his son.<BR>\n" );
document.write( "then father's age = 42+x , son's age = 10+x.<BR>\n" );
document.write( "42+x = 3(10+x)<BR>\n" );
document.write( "42 + x = 30 + 3x<BR>\n" );
document.write( "12 = 2x <BR>\n" );
document.write( "x = 6 \r<BR>\n" );
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document.write( "b) Let x be the number of years. father's age = 42+x , son's age = 10+x, daughter's age = 16+x <BR>\n" );
document.write( "42+x = 10+x + 16+ x<BR>\n" );
document.write( "x=16  </SPAN>\n" );
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