document.write( "Question 71395: Solve: 3x(to the 2nd power) - 2x - 4 = 0\r
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Algebra.Com's Answer #51070 by bucky(2189)\"\" \"About 
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\"3x%5E2+-+2x+-+4+=+0\"
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\n" ); document.write( "This equation does not factor nicely. So the best way to solve it is to use the quadratic
\n" ); document.write( "formula. (The quadratic formula is derived by the method of completing the square,
\n" ); document.write( "so it is a generalized form of the process of completing the square.)
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\n" ); document.write( "The quadratic formula says that for an expression of the quadratic form:
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\n" ); document.write( "\"ax%5E2+%2B+bx+%2B+c+=+0\"
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\n" ); document.write( "The value(s) of x is given by the equation:
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\n" ); document.write( "\"x+=+-%28b%29%2F2a+%2B-+%28sqrt%28b%5E2+-+4%2Aa%2Ac%29%29%2F2a\"
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\n" ); document.write( "By comparing the numeric values given in the problem with the letters in the quadratic
\n" ); document.write( "form you can see that a (the coefficient of x^2) is 3, b (the coefficient of x is -2,
\n" ); document.write( "and c (the constant) is -4. Now all you have to do is substitute those values into the
\n" ); document.write( "equation for x. When you do you get:
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\n" ); document.write( "The first stage of simplification results in:
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\n" ); document.write( "\"x+=+2%2F6+%2B-+%28sqrt%284+%2B+48%29%29%2F6\"
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\n" ); document.write( "Notice that the square root term becomes \"sqrt%2852%29\". This equals \"sqrt%2813%2A4%29\"
\n" ); document.write( "which furthermore can be written as \"sqrt%2813%29+%2A+sqrt%284%29\". But the square root of
\n" ); document.write( "4 is 2, so the final reduction is \"2%2Asqrt%2813%29\". Put this into the equation as a
\n" ); document.write( "replacement for \"sqrt%284%2B48%29\" to get:
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\n" ); document.write( "\"x+=+2%2F6+%2B-+%282%2Asqrt%2813%29%29%2F6\"
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\n" ); document.write( "The six is a common denominator so you can put both numerators over this common denominator
\n" ); document.write( "to get:
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\n" ); document.write( "\"x+=+%282+%2B-+%282%2Asqrt%2813%29%29%29%2F6\"
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\n" ); document.write( "And since 2 is a factor of both terms in the numerator it can be made a multiplier
\n" ); document.write( "of the two numerator terms as follows:
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\n" ); document.write( "\"x+=+%282%2A%281+%2B-+sqrt%2813%29%29%29%2F6\"
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\n" ); document.write( "Finally, the multiplier of two in the numerator and the denominator have a common
\n" ); document.write( "factor of 2. Cancel it to make the final answer:
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\n" ); document.write( "\"x+=+%28%281+%2B-+sqrt%2813%29%29%29%2F3\"
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\n" ); document.write( "These are the two values for x.
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\n" ); document.write( "\"x+=+%28%281+%2B+sqrt%2813%29%29%29%2F3\" and \"x+=+%28%281+-+sqrt%2813%29%29%29%2F3\"
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\n" ); document.write( "Hope this helps you to see how to work this equation. Make sure that you work through
\n" ); document.write( "each step so you can see how to identify a, b, and c in a quadratic equation, and then
\n" ); document.write( "how to work the numbers. This method is useful because it is a general method that can
\n" ); document.write( "be used to evaluate and solve quadratic equations, some significantly more complex
\n" ); document.write( "than this one.
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