document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=847666>Question 847666</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Given the equation, 9x + 3y =-6, write a second linear equation to create a system that has exactly only one solution. How do you do this ? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #510615 by </B><A HREF=/tutors/aboutme.mpl?userid=richwmiller><B>richwmiller(17219)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=richwmiller><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=richwmiller><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=510615\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Lines that intersect have only one solution.<BR>\n" );
document.write( "Lines that are perpendicular intersect.<BR>\n" );
document.write( "So one way is to write an equation that is perpendicular.<BR>\n" );
document.write( "Lines that are perpendicular have slopes that multiply to -1\r<BR>\n" );
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document.write( "9x + 3y =-6<BR>\n" );
document.write( "is the same line as <BR>\n" );
document.write( "y = -3 x-2 with slope<BR>\n" );
document.write( "-3<BR>\n" );
document.write( "1/3 would be the slope of a line perpendicular.<BR>\n" );
document.write( "y =  x/3-2 or y = 1/3*x-2 </SPAN>\n" );
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