document.write( "Question 847552: Mark Wright can hit the bull's eye with his 22 rifle 30% of the time. He fires 5 shots.\r
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Algebra.Com's Answer #510539 by ewatrrr(24785)\"\" \"About 
You can put this solution on YOUR website!
 
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document.write( "Hi,
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document.write( "Note: The probability of x successes in n trials is: 
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document.write( "P = nCx* \"p%5Ex%2Aq%5E%28n-x%29\" where p and q are the probabilities of success and failure respectively. 
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document.write( "In this case p = .30 and q = .70   and n = 5 
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document.write( "\"+nCx+=+%28n%21%29%2Fx%21%28n+-+x%29%21%29\" 
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document.write( "Using the 'formula' is the 0r
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document.write( "Using TI Calculator
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document.write( "a. binompdf(5,.30, 0) = .1681  0r P = (.30)^0(.70)^5
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document.write( " binompdf(5,.30, 1) = .3602    0r P = 5(.30)^1(.70)^4
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document.write( "binompdf(5,.30, 2) =  .3087    0r P = 10(.30)^2(.70)^3
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document.write( "binompdf(5,.30,3) =   .1323   0r  P = 10(.30)^3(.70)^2
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document.write( "binompdf(5,.30, 4) =  .0284   0r P = 5(.30)^4(.70)^1
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document.write( "binompdf(5,.30, 5) =  .0024   0r P = (.30)^5(.70)^0
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document.write( "c. P(x≥ 2) = 1 - P(x=0)- P(x=1) =   1 - .1681 - .3602
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document.write( "0r  Using TI
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document.write( "1 – binomcdf(n, p, largest x-value) = 1 - binomcdf(5,.30, 1) \n" );
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