document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=847499>Question 847499</A>: <I><SPAN STYLE=\"word-break: break-all;\"> assume that 2 out 5 shipments coming from a particular supplier do not arrive on time. what is the probability that among 8 shipments which this supplier send, a.)exactly 3 will not arrive on time b.) exactly 6 will arrive on time </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #510485 by </B><A HREF=/tutors/aboutme.mpl?userid=swincher4391><B>swincher4391(1107)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=swincher4391><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=swincher4391><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=510485\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> p (the probability of not arriving on time)= 2/5 from our first statement.\r<BR>\n" );
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document.write( "We can also figure out that n = 8.\r<BR>\n" );
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document.write( "a)  binomial with n=8, x= 3, p =2/5\r<BR>\n" );
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document.write( "(8 choose 3)(2/5)^3 *(3/5)^5 = .2787\r<BR>\n" );
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document.write( "b) binomial with n=8 x=2 (since arriving on time is considered a failure, 8-6 = 2 successes), and p = 2/5\r<BR>\n" );
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document.write( "(8 choose 2) * (2/5)^2 * (3/5)^6 = .2090\r<BR>\n" );
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document.write( "If you'd like, change your definition of success to be on time.  Then n=8, p =3/5 x = 6\r<BR>\n" );
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document.write( "(8 choose 6) * (3/5)^6 * (2/5)^2 = .2090\r<BR>\n" );
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document.write( "Partitioning 8 into 6 and 2 is the same as partitioning 8 into 2 and 6. This is why we get the same result. Just remember to know what you consider a success and the rest will fall into place. </SPAN>\n" );
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