document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=847484>Question 847484</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Sir,\r<BR>\n" );
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document.write( "10 years ago a man has 6 times as old as his daughter. After 10 years he will be twise as old as his daughter. Find their present age.\r<BR>\n" );
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document.write( "thank you-Bindu </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #510470 by </B><A HREF=/tutors/aboutme.mpl?userid=swincher4391><B>swincher4391(1107)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=swincher4391><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=swincher4391><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=510470\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> let  m be the age of the man  let d be the age of the daughter\r<BR>\n" );
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document.write( "(m-10) = 6*(d-10)\r<BR>\n" );
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document.write( "m+10 = 2*(d+10)\r<BR>\n" );
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document.write( "m-10 = 6d - 60<BR>\n" );
document.write( "m+10 = 2d + 20\r<BR>\n" );
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document.write( "m = 6d -50 (solving first one for m)\r<BR>\n" );
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document.write( "6d-50 + 10 = 2d + 20\r<BR>\n" );
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document.write( "6d -40 = 2d + 20\r<BR>\n" );
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document.write( "4d = 60\r<BR>\n" );
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document.write( "d = 15\r<BR>\n" );
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document.write( "m = 6(15) - 50 = 40\r<BR>\n" );
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document.write( "The man is 40, his daughter is 15. </SPAN>\n" );
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