document.write( "Question 847448: Please help me solve this logarithmic problem;
\n" ); document.write( "Solve for x in R^(3-2x)=sqrt(3)
\n" ); document.write( "Here is what my working out looks like.
\n" ); document.write( "3-2xlogR=(1/2)log3
\n" ); document.write( "3-2x=log3/2logR
\n" ); document.write( "-2x=((log3/2logR)-3)
\n" ); document.write( "x=-1/2((3/2)-log3/4logR)
\n" ); document.write( "

Algebra.Com's Answer #510444 by Alan3354(69443)\"\" \"About 
You can put this solution on YOUR website!
Solve for x in R^(3-2x)=sqrt(3)
\n" ); document.write( "Here is what my working out looks like.
\n" ); document.write( "3-2xlogR=(1/2)log3
\n" ); document.write( "3-2x=log3/2logR
\n" ); document.write( "-2x=((log3/2logR)-3)
\n" ); document.write( "x=-1/2((3/2)-log3/4logR)
\n" ); document.write( "------------------
\n" ); document.write( "It's correct but for the last step.
\n" ); document.write( "==============
\n" ); document.write( "(3-2x)logR = log(3)/2
\n" ); document.write( "3-2x = log(3)/(2logR)
\n" ); document.write( "-2x = -3 + log(3)/(2logR)
\n" ); document.write( "x = 3/2 - log(3)/(4log(R))
\n" ); document.write( "\"x+=+3%2F2+-+log%284%29%2Flog%28R%5E4%29\"
\n" ); document.write( "
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