document.write( "Question 847448: Please help me solve this logarithmic problem;
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document.write( "Solve for x in R^(3-2x)=sqrt(3)
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document.write( "Here is what my working out looks like.
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document.write( "3-2xlogR=(1/2)log3
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document.write( "3-2x=log3/2logR
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document.write( "-2x=((log3/2logR)-3)
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document.write( "x=-1/2((3/2)-log3/4logR) \n" );
document.write( "
Algebra.Com's Answer #510444 by Alan3354(69443)![]() ![]() You can put this solution on YOUR website! Solve for x in R^(3-2x)=sqrt(3) \n" ); document.write( "Here is what my working out looks like. \n" ); document.write( "3-2xlogR=(1/2)log3 \n" ); document.write( "3-2x=log3/2logR \n" ); document.write( "-2x=((log3/2logR)-3) \n" ); document.write( "x=-1/2((3/2)-log3/4logR) \n" ); document.write( "------------------ \n" ); document.write( "It's correct but for the last step. \n" ); document.write( "============== \n" ); document.write( "(3-2x)logR = log(3)/2 \n" ); document.write( "3-2x = log(3)/(2logR) \n" ); document.write( "-2x = -3 + log(3)/(2logR) \n" ); document.write( "x = 3/2 - log(3)/(4log(R)) \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " |