document.write( "Question 847345: Use inverse functions where needed to find all solutions of the equation in the interval [0, 2π)
\n" ); document.write( "tan^2 x − 5 tan x − 6 = 0
\n" ); document.write( "sec^2 x − 4 tan x = −2
\n" ); document.write( "2 cos^2 x + 7 sin x = 5
\n" ); document.write( "Cot^2 x − 25 = 0
\n" ); document.write( "tan^2 x + tan x − 6 = 0
\n" ); document.write( "2 cos^2 x + 7 sin x = 5
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Algebra.Com's Answer #510432 by stanbon(75887)\"\" \"About 
You can put this solution on YOUR website!
Use inverse functions where needed to find all solutions of the equation in the interval [0, 2π)
\n" ); document.write( "tan^2 x − 5 tan x − 6 = 0
\n" ); document.write( "Factor:
\n" ); document.write( "(tan-6)(t+1) = 0
\n" ); document.write( "tan(x) = 6 or tan(x) = -1
\n" ); document.write( "----
\n" ); document.write( "x = arctan(6) or tan(x) = -1
\n" ); document.write( "------
\n" ); document.write( "x = 1.4056.. or x = (pi+1.4056) or x = (3/4)pi or (7/4)pi
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\n" ); document.write( "sec^2 x − 4 tan x = −2
\n" ); document.write( "(1+tan^2(x))-4tan(x) = -2
\n" ); document.write( "tan^2(x) - 4tan(x) +3 = 0
\n" ); document.write( "(tan(x)-3)(tan(x)-1) = 0
\n" ); document.write( "tan(x) = 3 or tan(x) = 1
\n" ); document.write( "----
\n" ); document.write( "x = arctan(3) or x = arctan(1)
\n" ); document.write( "x = 1.23 or x = pi+1.23 or x = (pi/4) or x = (5/4)pi
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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