document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=847415>Question 847415</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The width of a rectangle is 4 centimeters.  If the length of the rectangle were doubled, its perimeter would increase by 12 centimeters. What is the area of the original rectangle?<BR>\n" );
document.write( "I try:<BR>\n" );
document.write( "P = 2(w+l)<BR>\n" );
document.write( "P+12 = 2(4+2l)<BR>\n" );
document.write( "P+12 = 8+4l<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #510419 by </B><A HREF=/tutors/aboutme.mpl?userid=josgarithmetic><B>josgarithmetic(39617)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=josgarithmetic><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=510419\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> w for width, L for Length.<BR>\n" );
document.write( "w=4 and p for perimeter, <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=highlight_green%282%2Aw%2B2%2AL=p%29 ALIGN=MIDDLE  ALT=\"highlight_green%282%2Aw%2B2%2AL=p%29\"   DISABLED_style= \"max-width:90%; height:auto;\" >.<BR>\n" );
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document.write( "If 2L for length, then perimeter is p+12.<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=highlight_green%282w%2B2%282L%29=p%2B12%29 ALIGN=MIDDLE  ALT=\"highlight_green%282w%2B2%282L%29=p%2B12%29\"   DISABLED_style= \"max-width:90%; height:auto;\" >.\r<BR>\n" );
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document.write( "Use the given value of w and simplify both equations.<BR>\n" );
document.write( "Original:  2*4+2L=p<BR>\n" );
document.write( "8+2L=p<BR>\n" );
document.write( "2L-p=-8<BR>\n" );
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document.write( "Doubled Length:  8+4L=p+12<BR>\n" );
document.write( "4L-p+8=12<BR>\n" );
document.write( "4L-p=4<BR>\n" );
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document.write( "The two equations are a system of equations in the variables, L and p.<BR>\n" );
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document.write( "2L-p=-8<BR>\n" );
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document.write( "4L-p=4<BR>\n" );
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document.write( "Suggestion is, use elimination method.  Subtract first equation from the second equation.<BR>\n" );
document.write( "4L-p-(2L-p)=4-(-8)<BR>\n" );
document.write( "2L=12<BR>\n" );
document.write( "L=6-------PART OF ANSWER.<BR>\n" );
document.write( "Use either equation to find p.<BR>\n" );
document.write( "-p=-2L-8<BR>\n" );
document.write( "p=2L+8<BR>\n" );
document.write( "p=2*6+8<BR>\n" );
document.write( "p=20---------(Nice to know but not really PART OF ANSWER).\r<BR>\n" );
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document.write( "All the question really asks is, what is the AREA of the original rectangle.<BR>\n" );
document.write( "Area of that will be <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=w%2AL=4%2A6=highlight%2824%2Acm%5E2%29 ALIGN=MIDDLE  ALT=\"w%2AL=4%2A6=highlight%2824%2Acm%5E2%29\"   DISABLED_style= \"max-width:90%; height:auto;\" > </SPAN>\n" );
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