document.write( "Question 847420: A change machine at an arcade gives change for $1 bills and $5 bills. If during a particular day, 200 bills were inserted into the machine and the total vaule was $300, how many $1 bills were inserted into the machine?
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document.write( "A) 25
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document.write( "B)75
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document.write( "C)125
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document.write( "D)175
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document.write( " Can you please show me how to solve it? I already know the answer is D- 175 but I just don't know how to get that. \n" );
document.write( "
Algebra.Com's Answer #510407 by jim_thompson5910(35256)![]() ![]() ![]() You can put this solution on YOUR website! Let \r \n" ); document.write( "\n" ); document.write( "x = number of $1 bills \n" ); document.write( "y = number of $5 bills\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "There are 200 bills of just $1 and $5 bills. So the two must add to 200\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "x + y = 200\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Solve for y to get y = 200 - x\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "---------------------------------\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "If you have x $1 bills and y $5 bills, then you'll have a total of x + 5y dollars. But we know this total is also equal to $300, so\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "x + 5y = 300\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Replace each copy of y with 200 - x (since above we know that y = 200 - x) to get\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "x + 5y = 300\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "x + 5(y) = 300\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "x + 5(200 - x) = 300\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "x + 5(200 - x) = 300\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Notice how y is completely gone now. Now solve for x\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "x + 5(200 - x) = 300\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "x + 5(200) + 5(-x) = 300\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "x + 1000 - 5x = 300\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "-4x + 1000 = 300\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "-4x = 300 - 1000\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "-4x = -700\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "x = -700/(-4)\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "x = 175\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "We could stop here, but let's keep going to find y\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "y = 200 - x\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "y = 200 - 175\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "y = 25\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "This bit is extra, but it helps to know how to find it (if asked).\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "=======================================================\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Answer:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Since x = 175, this means that there are 175 one dollar bills.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Note: if you forget what x is, look back up at the definitions above. This is why it helps to set these up first.\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |