document.write( "Question 847330: Find an equation of the circle that has center (4,-6) and passes through (-3,-4) \n" ); document.write( "
Algebra.Com's Answer #510352 by MathLover1(20850)\"\" \"About 
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The standard form of the equation for a circle is: \r
\n" ); document.write( "\n" ); document.write( "\"+%28x+-+h%29%5E2+%2B+%28y+%2B+k%29%5E2+=+r%5E2\" where \"h+\" is the \"x\" coordinate of the center of the circle , \"k\" is the \"y\" coordinate of the center of the circle, and \"r+\" is the radius of the circle .\r
\n" ); document.write( "\n" ); document.write( "the circle that has center (4,-6) and passes through (-3,-4) \r
\n" ); document.write( "\n" ); document.write( " given:
\n" ); document.write( " the center of the circle at (\"4\" ,\"-+6\")
\n" ); document.write( "one point the circle passes through: (\"-3\",\"-4\") \r
\n" ); document.write( "\n" ); document.write( "The only thing we are missing to complete the equation for the circle is to know (if given) or derive (if not given), \"r\", the radius of the circle. \r
\n" ); document.write( "\n" ); document.write( " With the two points given: center (\"4\" ,\"-+6\") and circle passes through (\"-3\",\"-4\") ; if we connect those two points together, that line will be equal the radius of the circle. \r
\n" ); document.write( "\n" ); document.write( "To determine the radius, think about a right triangle that has as its \"\"a\"\" side and \"\"b\"\" side the rise and run difference between the two given points. And, knowing the Pythagorean theorem to determine the hypotenuse of a right triangle: \r
\n" ); document.write( "\n" ); document.write( "\"c%5E2=+a%5E2+%2B+b%5E2+\"\r
\n" ); document.write( "\n" ); document.write( " We know that in in this instance the hypotenuse is equal to the radius of our circle, so we will substitute \"r\" for \"c\".
\n" ); document.write( "\"+r%5E2=a%5E2+%2B+b%5E2+\"\r
\n" ); document.write( "\n" ); document.write( "If we take the square root of both sides of the previous equation we get:
\n" ); document.write( "\"+r+=+sqrt%28a%5E2+%2B+b%5E2%29\"\r
\n" ); document.write( "\n" ); document.write( " To solve, you need: \r
\n" ); document.write( "\n" ); document.write( "\"a\" = the difference in the two \"x+\"coordinates (from the two points given):
\n" ); document.write( "\"a+=+4+-+%28-3%29+=+4%2B3=7\" \r
\n" ); document.write( "\n" ); document.write( "and \"b+\" = the difference in the two y coordinates (from the two points given): \r
\n" ); document.write( "\n" ); document.write( "\"b+=-+6+-+%28-4%29=-6%2B4+=+-2\" \r
\n" ); document.write( "\n" ); document.write( "then, \"+r+=+sqrt%287%5E2+%2B+%28-2%29%5E2%29\"\r
\n" ); document.write( "\n" ); document.write( "\"+r+=+sqrt%2849%2B4+%29+\"
\n" ); document.write( "\"r+=+sqrt%2853%29\"
\n" ); document.write( "To return to the original problem: determine the equation for the circle with the given center point and passing through the given point: \r
\n" ); document.write( "\n" ); document.write( " \"%28x+-+4%29%5E2+%2B+%28y+%2B6%29%5E2+=+%28sqrt%2853%29%29%5E2\" which could be simplified to\r
\n" ); document.write( "\n" ); document.write( " \"+%28x+-+4%29%5E2+%2B+%28y+%2B+6%29%5E2+=53+\"\r
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