document.write( "Question 71334: martin and anna buy books at a sale. martin buys 3 hardcover books and 4 paperback books for $6.50. Anna buys 2 hardcover books and 6 paperback books for $6.00. What is the cost, in dollars, of each hardcover book? \n" ); document.write( "
Algebra.Com's Answer #51034 by checkley75(3666)![]() ![]() ![]() You can put this solution on YOUR website! 3h+4p=6.50 \n" ); document.write( "2h+6p=6.00 noe solve for h \n" ); document.write( "2h=-6p+6.00 \n" ); document.write( "h=-6p/2+6.00/2 \n" ); document.write( "h=-3p+3.00 now substitute (-3p+3.00) for h in the first equation thus: \n" ); document.write( "3(-3p+3.00)+4p=6.50 \n" ); document.write( "-9p+9.00+4p=6.50 \n" ); document.write( "-9p+4p=6.50-9.00 \n" ); document.write( "-5p=-2.50 \n" ); document.write( "p=-2.50/-5 \n" ); document.write( "p=.50 is the price for the paper back books. \n" ); document.write( "now solve for h \n" ); document.write( "3h+4*.50=6.50 \n" ); document.write( "3h+2.00=6.50 \n" ); document.write( "3h=6.50-2.00 \n" ); document.write( "3h=4.50 \n" ); document.write( "h=4.50/3 \n" ); document.write( "h=1.50 cost of the hard cover books. \n" ); document.write( "proof \n" ); document.write( "2*1.50+6*.50=6.00 \n" ); document.write( "3.00+3.00=6.00 \n" ); document.write( "6.00=6.00 \n" ); document.write( " |