document.write( "Question 71334: martin and anna buy books at a sale. martin buys 3 hardcover books and 4 paperback books for $6.50. Anna buys 2 hardcover books and 6 paperback books for $6.00. What is the cost, in dollars, of each hardcover book? \n" ); document.write( "
Algebra.Com's Answer #51034 by checkley75(3666)\"\" \"About 
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3h+4p=6.50
\n" ); document.write( "2h+6p=6.00 noe solve for h
\n" ); document.write( "2h=-6p+6.00
\n" ); document.write( "h=-6p/2+6.00/2
\n" ); document.write( "h=-3p+3.00 now substitute (-3p+3.00) for h in the first equation thus:
\n" ); document.write( "3(-3p+3.00)+4p=6.50
\n" ); document.write( "-9p+9.00+4p=6.50
\n" ); document.write( "-9p+4p=6.50-9.00
\n" ); document.write( "-5p=-2.50
\n" ); document.write( "p=-2.50/-5
\n" ); document.write( "p=.50 is the price for the paper back books.
\n" ); document.write( "now solve for h
\n" ); document.write( "3h+4*.50=6.50
\n" ); document.write( "3h+2.00=6.50
\n" ); document.write( "3h=6.50-2.00
\n" ); document.write( "3h=4.50
\n" ); document.write( "h=4.50/3
\n" ); document.write( "h=1.50 cost of the hard cover books.
\n" ); document.write( "proof
\n" ); document.write( "2*1.50+6*.50=6.00
\n" ); document.write( "3.00+3.00=6.00
\n" ); document.write( "6.00=6.00
\n" ); document.write( "
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