document.write( "Question 847244: \n" ); document.write( "
Algebra.Com's Answer #510328 by Edwin McCravy(20055)\"\" \"About 
You can put this solution on YOUR website!
Limx>0 (1-2x/1+2x)^1/3x
\n" ); document.write( "
\r\n" );
document.write( "You didn't put parentheses to show where your numerators and\r\n" );
document.write( "denominators begin and end, so I will just guess that you meant\r\n" );
document.write( "this:\r\n" );
document.write( "\r\n" );
document.write( "\r\n" );
document.write( "\r\n" );
document.write( "We find the limit of the natural logarithm\r\n" );
document.write( "of the expression\r\n" );
document.write( "\r\n" );
document.write( "\r\n" );
document.write( "\r\n" );
document.write( "Use a rule of logarithms:\r\n" );
document.write( "\r\n" );
document.write( "\r\n" );
document.write( "\r\n" );
document.write( "When we substitute 0 for x into\r\n" );
document.write( "\r\n" );
document.write( "\"%28expr%281%2F3%29x%29ln%28%281-2x%29%2F%281%2B2x%29%29%5E%22%22\"\r\n" );
document.write( "\r\n" );
document.write( "\"%28expr%281%2F3%290%29ln%28%281-2%2A0%29%2F%281%2B2%2A0%29%29%5E%22%22\"\r\n" );
document.write( "\r\n" );
document.write( "\"%280%29ln%281%2F1%29\" = 0\r\n" );
document.write( "\r\n" );
document.write( "Since the natural logarithm of the function approaches 0,\r\n" );
document.write( "the function must approach the number which has the natural\r\n" );
document.write( "logarithm of 0, which is 1.  Therefore we can conclude:\r\n" );
document.write( "\r\n" );
document.write( "\"%22%22=%22%22\"\"1\"\r\n" );
document.write( "\r\n" );
document.write( "Edwin

\n" ); document.write( "
\n" ); document.write( "
\n" );