document.write( "Question 9378: Here is the second problem that I was talking about in another submitted question. A friend of mine thinks that the answer that we found to this question is wrong, but if it is than I don't know how to solve it. Could you help us. It is also a elipse problem that reads-\r
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document.write( "Graph the equation and find the coordinates of the foci.\r
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document.write( "(25x^2)-(144Y^2)= 3600\r
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document.write( "I think that there might be a mistake in this problem, but what do I know? That's why I'm asking you. \n" );
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Algebra.Com's Answer #5103 by mathmaven53(29)![]() ![]() ![]() You can put this solution on YOUR website! 25x^2 - 144y^2 = 3600\r \n" ); document.write( "\n" ); document.write( " Divide both sides by 3600 and simplify\r \n" ); document.write( "\n" ); document.write( " x^2/144 - y^2/25 = 1\r \n" ); document.write( "\n" ); document.write( " This is the equation of a hyperbola.\r \n" ); document.write( "\n" ); document.write( " In general x^/a^2 - y^2/b^2 = 1 is the equation of a hyperbola for nonzero a and b\r \n" ); document.write( "\n" ); document.write( " In its derivation the quantity b^2 = c^2 - a^2 where c is the x coordinate of a focus.\r \n" ); document.write( "\n" ); document.write( " We have a^2 = 144 and b^2 = 25\r \n" ); document.write( "\n" ); document.write( " So c^2 = a^2 + b^2\r \n" ); document.write( "\n" ); document.write( " = 169\r \n" ); document.write( "\n" ); document.write( " So the hyperbola x^2/144 - y^2/25 = 1 has foci at (-c,0) and (c,0)\r \n" ); document.write( "\n" ); document.write( " In other words foci at (-13,0) and (13,0) \n" ); document.write( " \n" ); document.write( " |