document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=847209>Question 847209</A>: <I><SPAN STYLE=\"word-break: break-all;\"> 1. Calculate the probability of the following<BR>\n" );
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document.write( "Assuming a probability of 0.5 that any child born will be a boy, the probability of any family of five children having no girls\r<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #510269 by </B><A HREF=/tutors/aboutme.mpl?userid=swincher4391><B>swincher4391(1107)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=swincher4391><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=swincher4391><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=510269\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> We can assume that the event of having a boy has no impact on the next child being a boy or girl. (you can almost think of it as flipping a coin: heads is boy, tails is girl. Me getting heads last time doesn't make it any more likely the next flip).  The term we use for this is independent.\r<BR>\n" );
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document.write( "P[no girl] = P[boy] = 0.5\r<BR>\n" );
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document.write( "P[5 boys] = P[boy]^5 = 0.5^5 = 0.0313 </SPAN>\n" );
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