document.write( "Question 847208: hello,
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document.write( "if I have (z,+) as a group ,
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document.write( "h={2x,x belongs z)
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document.write( "h={-8,-4,-2,0,2,4,8}=2z
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document.write( "2z C z
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document.write( "0 belongs to 2z(0=2*0) and h!= empty set
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document.write( "how can i show that 2z is a subgroup of z ? \n" );
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Algebra.Com's Answer #510267 by swincher4391(1107)![]() ![]() You can put this solution on YOUR website! Ah, abstract algebra. Good times.\r \n" ); document.write( "\n" ); document.write( "First off, let's think about how we can show how one set is a subgroup of another.\r \n" ); document.write( "\n" ); document.write( "We must show closure, identity, and an inverse element. \r \n" ); document.write( "\n" ); document.write( "Let's recap. We have h = {2x | where x is an integer}\r \n" ); document.write( "\n" ); document.write( "We want to show that 2z is a subgroup of z under the additive operator.\r \n" ); document.write( "\n" ); document.write( "Closure under addition:\r \n" ); document.write( "\n" ); document.write( "Let 2x and 2y be integers.\r \n" ); document.write( "\n" ); document.write( "Then 2x + 2y = 2(x+y) which exists in 2z.\r \n" ); document.write( "\n" ); document.write( "Identity:\r \n" ); document.write( "\n" ); document.write( "We know that in Z the identity element is 0. Since we have that 0 = 2*0, 0 exists in 2z.\r \n" ); document.write( "\n" ); document.write( "Inverse: \r \n" ); document.write( "\n" ); document.write( "Suppose we have some 2x in Z. The additive inverse for 2x is -2x and -2x = 2*(-x) which means -2x exists in 2z\r \n" ); document.write( "\n" ); document.write( "Hence 2z is a subgroup of z under addition.\r \n" ); document.write( "\n" ); document.write( "Note the upshot is we try to find elements that have the form 2 * (something).\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |