document.write( "Question 845900: let cos A = -5/13 with A in Q2 and sin B= 3/5 with B in Q1\r
\n" ); document.write( "\n" ); document.write( "Find 1. CSC(A-B) 2. TAN(A+B) 3. SEC(A+B) 4. In what Q does (A+B) terminate?
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Algebra.Com's Answer #510258 by lwsshak3(11628)\"\" \"About 
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let cos A = -5/13 with A in Q2 and sin B= 3/5 with B in Q1
\n" ); document.write( "Find 1. CSC(A-B) 2. TAN(A+B) 3. SEC(A+B) 4. In what Q does (A+B) terminate?
\n" ); document.write( "***
\n" ); document.write( "cos A=-5/13
\n" ); document.write( "sin A=12/13
\n" ); document.write( "..
\n" ); document.write( "sin B=3/5
\n" ); document.write( "cos B=4/5
\n" ); document.write( "..
\n" ); document.write( "1. csc (A-B)=1/sin(A-B)
\n" ); document.write( "sin(A-B)=sin A*cos B-cos A*sinB=12/13*4/5(-(-5/13)*3/5)=48/65+15/65=63/65
\n" ); document.write( "csc(A-B)=65/63
\n" ); document.write( "..
\n" ); document.write( "3.sec (A+B)=1/cos(A+B)
\n" ); document.write( "cos(A+B)=cos A*cos B+sin A*sinB=-5/13*4/5-12/13*3/5)=-20/65-36/65=-56/65
\n" ); document.write( "sec(A+B)=-65/56
\n" ); document.write( "..
\n" ); document.write( "2. tan(A+B)=sin(A+B)/cos(A+B)
\n" ); document.write( "sin(A+B)=sin A*cos B+cos A*sinB=12/13*4/5+(-5/13)*3/5)=48/65-15/65=33/65
\n" ); document.write( "tan(A+B)=-33/56
\n" ); document.write( "..
\n" ); document.write( "4. cos A=-5/13 (in Q2)
\n" ); document.write( "A≈112.62
\n" ); document.write( "sin B=3/5
\n" ); document.write( "B≈36.87˚
\n" ); document.write( "A+B≈149.49˚
\n" ); document.write( "A+B terminates in quadrant II
\n" ); document.write( "..
\n" ); document.write( "A-B≈75.75
\n" ); document.write( "calculator check:
\n" ); document.write( "sin(A-B)≈sin(75.75)≈0.9692
\n" ); document.write( "exact value=63/65≈0.9692
\n" ); document.write( "..
\n" ); document.write( "sin(A+B)≈sin(149.49)≈0.5077
\n" ); document.write( "exact value=33/65≈0.5077
\n" ); document.write( "..
\n" ); document.write( "cos(A+B)≈cos(149.49)≈-0.8615
\n" ); document.write( "exact value=-56/65≈-0.8615
\n" ); document.write( "..
\n" ); document.write( "tan(A+B)=tan(149.49)=-0.5892
\n" ); document.write( "exact value=-33/56≈-0.5892
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