document.write( "Question 847203: 1. Calculate the probability of the following
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "c. assuming a probability of any arrival at an emergency room being an emergency as 0.646, and assuming that arrivals are independent, the probability of the next four arrivals being all emergencies\r
\n" ); document.write( "\n" ); document.write( "Assuming (c),the probability of the next five arrivals being all non-emergencies. \r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "
\n" ); document.write( "

Algebra.Com's Answer #510256 by swincher4391(1107)\"\" \"About 
You can put this solution on YOUR website!
Probability of 1 emergency = 1-.646 [since they are complements]\r
\n" ); document.write( "\n" ); document.write( "Through INDEPENDENCE, probability of 5 non emergencies:\r
\n" ); document.write( "\n" ); document.write( "(1-.646)^5 = .0056
\n" ); document.write( "
\n" ); document.write( "
\n" );