document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=847202>Question 847202</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Two dice are thrown once. Find the probability of getting a multiple of 3 on the first die or a total of 8. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #510255 by </B><A HREF=/tutors/aboutme.mpl?userid=swincher4391><B>swincher4391(1107)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=swincher4391><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=swincher4391><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=510255\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> P[multiple of 3 on the first die] =  1/3<BR>\n" );
document.write( "ways to get a total of 8:\r<BR>\n" );
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document.write( "(2,6)<BR>\n" );
document.write( "(3,5)<BR>\n" );
document.write( "(4,4)<BR>\n" );
document.write( "(5,3)<BR>\n" );
document.write( "(6,2)\r<BR>\n" );
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document.write( "So 5/36 ways to sum to 8.\r<BR>\n" );
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document.write( "Notice that our roll of (3,5) is being counted in both cases so we must subtract it once. \r<BR>\n" );
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document.write( "Putting it all together:<BR>\n" );
document.write( "P[multiple of 3 on first, sum to 8] =  1/3 + 5/36 - 1/36 = 4/9\r<BR>\n" );
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document.write( " </SPAN>\n" );
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