document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=846293>Question 846293</A>: <I><SPAN STYLE=\"word-break: break-all;\"> y=2x<BR>\n" );
document.write( "3x+3y=-18\r<BR>\n" );
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document.write( "Y=?<BR>\n" );
document.write( "X=?<BR>\n" );
document.write( "Solve for X and Y using substitution\r<BR>\n" );
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document.write( " </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #510252 by </B><A HREF=/tutors/aboutme.mpl?userid=dg181625><B>dg181625(2)</B></A><img src=\"/images/stars/iconNewId_16x16.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=dg181625><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=510252\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> y=2x<BR>\n" );
document.write( "3x+3y=-18 <BR>\n" );
document.write( "Y=?<BR>\n" );
document.write( "X=?\r<BR>\n" );
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document.write( "Since y is already isolated, just plug it in the second equation to find x.\r<BR>\n" );
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document.write( "3(x) + 3(2x) = -18<BR>\n" );
document.write( "3x + 6x = -18<BR>\n" );
document.write( "9x = -18<BR>\n" );
document.write( "x = -2 \r<BR>\n" );
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document.write( "X is equal to -2. So just plug and chug in order to find y. \r<BR>\n" );
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document.write( "y = 2(x)<BR>\n" );
document.write( "y = 2(-2)<BR>\n" );
document.write( "y = -4  </SPAN>\n" );
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