document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=847193>Question 847193</A>: <I><SPAN STYLE=\"word-break: break-all;\"> 1. Calculate the probability of the following<BR>\n" );
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document.write( "assuming a probability of any arrival at an emergency room being an emergency as 0.646, and assuming that arrivals are independent, the probability of the next four arrivals being all emergencies						<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #510246 by </B><A HREF=/tutors/aboutme.mpl?userid=swincher4391><B>swincher4391(1107)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=swincher4391><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=swincher4391><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=510246\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The key word is that the arrivals are INDEPENDENT. Normally in order to find P(AB), we must find P(A) * P(B|A). But notice that since they are independent, A doesn't affect the outcome of B. Thus we can just multiply the resulting probabilities as is. This is very handy because the probability of 4 emergencies is P[emergency]^4 = .646^4 = .1742 </SPAN>\n" );
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