document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=847186>Question 847186</A>: <I><SPAN STYLE=\"word-break: break-all;\"> how many combinations using $1, $.50, $.20, $.10 to make $2.60 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #510245 by </B><A HREF=/tutors/aboutme.mpl?userid=swincher4391><B>swincher4391(1107)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=swincher4391><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=swincher4391><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=510245\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The answer is 558. Spoiler...there is a lot of work shown below. Please let me know if it becomes too confusing to follow. We first break the $1 into 3 cases, then from there we break the $.50 into 12 cases, then we break the $.20 from there into 70 cases, and then the $.10 is used to form 558 distinct cases. This could be achieved using a tree diagram. \r<BR>\n" );
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document.write( "Let's first find all possible numbers of each dollar that can be used to construct $2.60.\r<BR>\n" );
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document.write( "$1:  We can have 0,1,or 2 dollars without exceeding $2.60\r<BR>\n" );
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document.write( "If 0 $1, then we have $2.60 that we must create without using dollars.<BR>\n" );
document.write( "If 1 $1, then we have $1.60 that we must create without using dollars.<BR>\n" );
document.write( "If 2 $1, then we have $.60 that we must create without using dollars.\r<BR>\n" );
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document.write( "We break into 3 subcases.\r<BR>\n" );
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document.write( "From $2.60 we can use 0,1,2,3,4,or 5 $.50<BR>\n" );
document.write( "From $1.60 we can use 0,1,2,or 3 $.50<BR>\n" );
document.write( "From $.60 we can use 0 or 1  $.50\r<BR>\n" );
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document.write( "Now we've broken into 12 subcases.\r<BR>\n" );
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document.write( "From $2.60 we can use 0 - 13  $.20  (14 subcases)<BR>\n" );
document.write( "From $2.10 we can use 0 - 10  $.20  (11)<BR>\n" );
document.write( "From $1.60 we can use 0 - 8   $.20  (9)<BR>\n" );
document.write( "From $1.10 we can use 0 - 5   $.20  (6)<BR>\n" );
document.write( "From $.60 we can use  0 - 3   $.20  (4)<BR>\n" );
document.write( "From $.10 we can use  0       $.20  (1)\r<BR>\n" );
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document.write( "From $1.60 we can use 0 - 8   $.20  (9)<BR>\n" );
document.write( "From $1.10 we can use 0 - 5   $.20  (6)<BR>\n" );
document.write( "From $.60 we can use  0 - 3   $.20  (4)<BR>\n" );
document.write( "From $.10 we can use  0       $.20  (1)\r<BR>\n" );
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document.write( "From $.60 we can use  0 - 3   $.20  (4)<BR>\n" );
document.write( "From $.10 we can use  0       $.20  (1)\r<BR>\n" );
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document.write( "Now we have 70 subcases (don't worry this is the last time)\r<BR>\n" );
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document.write( "From  $2.60 we have 26 subcases<BR>\n" );
document.write( "From  $2.40 we have 24 subcases<BR>\n" );
document.write( "From  $2.20 we have 22<BR>\n" );
document.write( "From  $2.00 we have 20<BR>\n" );
document.write( "From  $1.80 we have 18<BR>\n" );
document.write( "From  $1.60 we have 16<BR>\n" );
document.write( "From  $1.40 we have 14<BR>\n" );
document.write( "From  $1.20 we have 12<BR>\n" );
document.write( "From  $1.00 we have 10<BR>\n" );
document.write( "From  $0.80 we have 8<BR>\n" );
document.write( "From  $0.60 we have 6<BR>\n" );
document.write( "From  $0.40 we have 4<BR>\n" );
document.write( "From  $0.20 we have 2<BR>\n" );
document.write( "From  $0.00 we have 0\r<BR>\n" );
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document.write( "From  $2.10 we have 21<BR>\n" );
document.write( "19<BR>\n" );
document.write( "17<BR>\n" );
document.write( "15<BR>\n" );
document.write( "13<BR>\n" );
document.write( "11<BR>\n" );
document.write( "9<BR>\n" );
document.write( "7<BR>\n" );
document.write( "5<BR>\n" );
document.write( "3<BR>\n" );
document.write( "1\r<BR>\n" );
document.write( "\n" );
document.write( "16<BR>\n" );
document.write( "14<BR>\n" );
document.write( "12<BR>\n" );
document.write( "10<BR>\n" );
document.write( "8<BR>\n" );
document.write( "6<BR>\n" );
document.write( "4<BR>\n" );
document.write( "2<BR>\n" );
document.write( "0\r<BR>\n" );
document.write( "\n" );
document.write( "11<BR>\n" );
document.write( "9<BR>\n" );
document.write( "7<BR>\n" );
document.write( "5<BR>\n" );
document.write( "3<BR>\n" );
document.write( "1\r<BR>\n" );
document.write( "\n" );
document.write( "6<BR>\n" );
document.write( "4<BR>\n" );
document.write( "2<BR>\n" );
document.write( "0\r<BR>\n" );
document.write( "\n" );
document.write( "1\r<BR>\n" );
document.write( "\n" );
document.write( "16<BR>\n" );
document.write( "14<BR>\n" );
document.write( "12<BR>\n" );
document.write( "10<BR>\n" );
document.write( "8<BR>\n" );
document.write( "6<BR>\n" );
document.write( "4<BR>\n" );
document.write( "2<BR>\n" );
document.write( "0\r<BR>\n" );
document.write( "\n" );
document.write( "11<BR>\n" );
document.write( "9<BR>\n" );
document.write( "7<BR>\n" );
document.write( "5<BR>\n" );
document.write( "3<BR>\n" );
document.write( "1\r<BR>\n" );
document.write( "\n" );
document.write( "6<BR>\n" );
document.write( "4<BR>\n" );
document.write( "2<BR>\n" );
document.write( "0\r<BR>\n" );
document.write( "\n" );
document.write( "1\r<BR>\n" );
document.write( "\n" );
document.write( "6<BR>\n" );
document.write( "4<BR>\n" );
document.write( "2<BR>\n" );
document.write( "0\r<BR>\n" );
document.write( "\n" );
document.write( "1\r<BR>\n" );
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document.write( "Adding this all together gives us 558.\r<BR>\n" );
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document.write( " </SPAN>\n" );
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