document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=847137>Question 847137</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The ratio of the perimeter of rectangle P to the perimeter of rectangle Q is 2:5. The area of rectangle P is 12 square feet. What is the area of rectangle Q?<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #510229 by </B><A HREF=/tutors/aboutme.mpl?userid=josgarithmetic><B>josgarithmetic(39617)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=josgarithmetic><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=510229\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> x and y is width and length of rectangle P.<BR>\n" );
document.write( "xy=A for rectangle P<BR>\n" );
document.write( "2x+2y=p for rectangle P, using lowercase p for perimeter.\r<BR>\n" );
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document.write( "\"area of rect P is 12 ft^2\";<BR>\n" );
document.write( "A=xy=12.  <BR>\n" );
document.write( "You could find y as a formula and substitute into the perimeter equation for rectangle P.<BR>\n" );
document.write( "y=12/x;<BR>\n" );
document.write( "2x+2(12/x)=p<BR>\n" );
document.write( "2x+24/x=p\r<BR>\n" );
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document.write( "While being unproductive here, one should know that if the perimeters of P and Q are in a certain ratio, then the side lengths are also in this ratio.  If the two rectangles are similar, then the problem could be easier.\r<BR>\n" );
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document.write( "Rectangle P.<BR>\n" );
document.write( "x and y as before.<BR>\n" );
document.write( "2x+2y=p and xy=A, for P.\r<BR>\n" );
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document.write( "2/5 is Perimeter P to perimeter Q.<BR>\n" );
document.write( "Rectangle Q.<BR>\n" );
document.write( "2(5/2)x+2(5/2)y=perimQ<BR>\n" );
document.write( "2(5/2)(x+y)=perimQ<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=highlight%28%285%2F2%29%282x%2B2y%29=perimQ%29 ALIGN=MIDDLE  ALT=\"highlight%28%285%2F2%29%282x%2B2y%29=perimQ%29\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
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document.write( "(5/2)x(5/2)y=areaQ<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=highlight%28%285%2F2%29%5E2%2Axy=areaQ%29 ALIGN=MIDDLE  ALT=\"highlight%28%285%2F2%29%5E2%2Axy=areaQ%29\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "Recall that <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=highlight_green%28xy=12%2Aft%5E2%29 ALIGN=MIDDLE  ALT=\"highlight_green%28xy=12%2Aft%5E2%29\"   DISABLED_style= \"max-width:90%; height:auto;\" >.<BR>\n" );
document.write( "Substituting this value for xy, the area of P, into the \"areaQ\" equation, we can compute the area of rectangle Q.<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=%285%2F2%29%5E2%2A12=areaQ ALIGN=MIDDLE  ALT=\"%285%2F2%29%5E2%2A12=areaQ\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=%2825%2F4%29%2A12 ALIGN=MIDDLE  ALT=\"%2825%2F4%29%2A12\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=highlight%28highlight%28areaQ=75%29%29 ALIGN=MIDDLE  ALT=\"highlight%28highlight%28areaQ=75%29%29\"   DISABLED_style= \"max-width:90%; height:auto;\" > </SPAN>\n" );
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