document.write( "Question 847174: A radiator contains 5 quarts of fluid, 25% of which is antifreeze. How much fluid should be drained and replaced with pure antifreeze so that the new mixture is 50% antifreeze? \n" ); document.write( "
Algebra.Com's Answer #510228 by josgarithmetic(39618)\"\" \"About 
You can put this solution on YOUR website!
Drain v quarts of the 25% and replace with v quarts of the pure, 100%.\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Amount of antifreeze will be: \"5%2A25-v%2A25%2Bv%2A100\", which is 100 times larger because of using the percents unit. Simplify partway into \"25%2A5%2B%28100-25%29v\".\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "The equation for wanting 50% antifreeze result is:
\n" ); document.write( "\"highlight%28%2825%2A5%2B%28100-25%29v%29%2F5=50%29\".
\n" ); document.write( "Solve for v.\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "A next step could be the combined step, \"125%2B75v=250\"....
\n" ); document.write( "\"75v=125\"
\n" ); document.write( "\"v=125%2F75=%285%2A5%2A5%29%2F%283%2A5%2A5%29\"
\n" ); document.write( "\"highlight%28v=5%2F3=1%262%2F3%29\" quarts
\n" ); document.write( "
\n" );