document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=847151>Question 847151</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A 15N force acting at 15 degrees north of east and a 18N force acting at 79 degrees north of west act concurrently on an object. What is the magnitude and direction of a third force that produces equilibrium on the object? Show sketch and work. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #510204 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=510204\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> A 15N force acting at 15 degrees north of east and a 18N force acting at 79 degrees north of west act concurrently on an object. What is the magnitude and direction of a third force that produces equilibrium on the object? Show sketch and work.<BR>\n" );
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document.write( "x-component:: 15*cos(15 deg)+18cos(101 deg) = 11.05<BR>\n" );
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document.write( "y-component:: 15*sin(15 deg)+18sin(101 deg) = 21.55<BR>\n" );
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document.write( "magnitude = sqrt[11.05^2+21.55^2] = 24.22 <BR>\n" );
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document.write( "direction = arctan(21.55/11.05) = 62.85 degrees north of east<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
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