document.write( "Question 847130: I have been told I need to turn my logs into exponents to solve this equation but I am not sure how it works. I will do it as far as I know then please help me. I also need to know how when and why logs are used as exponents so I can solve future equations on my own. Here it is;\r
\n" ); document.write( "\n" ); document.write( "Base 3 (I don't have subscript), log3 (x+1) - 2 = log3 (x).
\n" ); document.write( "Here is what I have
\n" ); document.write( "Move the 2 over to the right side
\n" ); document.write( "Log3 (x+3) = log3 (x) + 2
\n" ); document.write( "Divide both sides by \"x\"
\n" ); document.write( "Log3 (x+1)/x = log3 (x)/x+ 2
\n" ); document.write( "Turn the logs into exponents of the base
\n" ); document.write( "3^log3 (x+1) = 3^log3 (x)/x +2 (the 2 is not an exponent)
\n" ); document.write( "The base and log bases cancel out and you have
\n" ); document.write( "Log3 (x+1)/x = 3^2
\n" ); document.write( "Log3 (x+1)/x = 9
\n" ); document.write( "Multiply both sides by x/x to get rid of the denominator and that leaves
\n" ); document.write( "X+1 = 9x
\n" ); document.write( "X + 1 - x = 9x - x
\n" ); document.write( "1 = 8x
\n" ); document.write( "Divide by 8
\n" ); document.write( "1/8 = x
\n" ); document.write( "If this is correct, why did the 2 become an exponent?\r
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Algebra.Com's Answer #510188 by ewatrrr(24785) $\"\"$ $\"About$

You can put this solution on YOUR website!

 
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document.write( "Hi,
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document.write( "       1st
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document.write( "       2nd
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document.write( "  9x = x+1
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document.write( "  8x = 1
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document.write( "   x = 1/8
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document.write( "  applied 2nd
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document.write( "  Applied 1st
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