document.write( "Question 846992: Two cars belonging to two brothers are in two towns two hundred miles apart. The brothers decide to meet for a cup of coffee. The first brother starts at 9:00A.M. driving 60mph. The second brother starts at 9:00A.M driving at 40mph. What time do they meet? \n" ); document.write( "

Algebra.Com's Answer #510045 by josmiceli(19441) $\"\"$ $\"About$

You can put this solution on YOUR website!
A simple way to do it is to think of
\n" ); document.write( "one driver as standing still and the other
\n" ); document.write( "driving at the sum of their speeds.
\n" ); document.write( "This will give you the time that they meet
\n" ); document.write( " $\"+d+=+r%2At+\"$
\n" ); document.write( " $\"+200+=+%28+60+%2B+40+%29%2At+\"$
\n" ); document.write( " $\"+t+=+200+%2F+100+\"$
\n" ); document.write( " $\"+t+=+2+\"$
\n" ); document.write( "9 AM plus 2 hrs = 11 AM they will meet
\n" ); document.write( "check:
\n" ); document.write( "1st driver:
\n" ); document.write( " $\"+d%5B1%5D+=+60t+\"$
\n" ); document.write( " $\"+d%5B1%5D+=+60%2A2+\"$
\n" ); document.write( " $\"+d%5B1%5D+=+120+\"$ mi
\n" ); document.write( "and
\n" ); document.write( " $\"+d%5B2%5D+=+40t+\"$
\n" ); document.write( " $\"+d%5B2%5D+=+40%2A2+\"$
\n" ); document.write( " $\"+d%5B2%5D+=+80+\"$
\n" ); document.write( "------------
\n" ); document.write( " $\"+d%5B1%5D%2B+d%5B2%5D+=+120+%2B+80+\"$
\n" ); document.write( " $\"+d%5B1%5D+%2B+d%5B2%5D+=+200+\"$
\n" ); document.write( "as it should\r
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